1=x^2+10x+25

Solution for 1=x^2+10x+25 equation:

1=x^2+10x+25

We move all terms to the left:

1-(x^2+10x+25)=0

We get rid of parentheses

-x^2-10x-25+1=0

We add all the numbers together, and all the variables

-1x^2-10x-24=0

a = -1; b = -10; c = -24;
Δ = b2-4ac
Δ = -102-4·(-1)·(-24)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*-1}=\frac{8}{-2}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*-1}=\frac{12}{-2}
=-6
$